![]() ![]() ![]() The following example demonstrates both successful and unsuccessful calls to Parse and TryParse. You can check for a null or empty string before attempting to parse it by calling the String.IsNullOrEmpty method. A string whose value is null or String.Empty fails to parse successfully. 3" (note the embedded space), "10e1" ( float.TryParse works here), and so on. For example, you can use decimal.TryParse to parse "10", "10.3", or " 10 ", but you can't use this method to parse 10 from "10X", "1 0" (note the embedded space), "10. Any white space within the string that forms the number causes an error. The Parse and TryParse methods ignore white space at the beginning and at the end of the string, but all other characters must be characters that form the appropriate numeric type ( int, long, ulong, float, decimal, and so on). When calling a Parse method, you should always use exception handling to catch a FormatException when the parse operation fails. If the string isn't in a valid format, Parse throws an exception, but TryParse returns false. The Parse method returns the converted number the TryParse method returns a boolean value that indicates whether the conversion succeeded, and returns the converted number in an out parameter. The Convert.ToInt32 method uses Parse internally. You use Parse or TryParse methods on the numeric type you expect the string contains, such as the System.Int32 type. Using a Convert method is more useful for general objects that implement IConvertible. It's slightly more efficient and straightforward to call a TryParse method (for example, int.TryParse("11", out number)) or Parse method (for example, var number = int.Parse("11")). If you’re interested in improving your C# skills, you might want to check out my recent post on C# interview questions.You convert a string to a number by calling the Parse or TryParse method found on numeric types ( int, long, double, and so on), or by using methods in the System.Convert class. I hope this has brought some clarity to the subject of converting a char to an int in C#. If you’re confident in your input is in the range ‘0’ – ‘9’ and speed is key, then you can do: var myInt = m圜har – ‘0’.If you want to handle fractional chars (like ½) consider using char.GetNumericValue(), but be aware it might turn -1 if the input doesn’t represent a char and the output is a double not an int.If you’re not sure if your char represents an in, use: int.TryParse(m圜har.ToString(), out var myInt).If you’re confident it’s an int, use: int.Parse(m圜har.ToString()).There’s more than one way to skin a cat, and there’s more than one way to convert a char to in int in C#: I don’t know about you, but I’m not one of r being careful, so I like to stick to methods that do the fiddly stuff for me, like int.TryParse() described above. You’ll see that this method does not have any in built error checking, so we again need to be careful and check the bounds of the result ourselves. ½ is now 141 which is of type System.Int32 Z is now 74 which is of type System.Int32 Var m圜hars = new char appears to be out of bounds") Ī is now 49 which is of type System.Int32 Of if you’re after a more complete example: using System If (!int.TryParse(m圜har.ToString(), out result)) Here’s an example of how to use it: int result If you’re not sure if your character represents an integer, but you want to try converting it anyway, then int.TryParse() is for you. You couple wrap this statement in a try catch block, but there is a neater way to handle these cases using int.TryParse: Convert a Char to an Int using int.TryParse() If you want further details on this, checkout the official docs.īut do bear in mind that you can expect a System.FormatException if the character you enter isn’t an int. Note the use of m圜har.ToString() to convert the char into a string as there’s no overload of int.Parse() that takes a char. If you’re certain that your char is an integer and are prepared to accept an exception being thrown if you’re wrong, then int.Parse() is your friend: var m圜har = '7' Convert a Char to an Int using int.Parse()Īs mentioned in the introduction, int.Parse() is the simplest method. Here I’ll give you a few different options for how to convert a char to an int, together with a discussion of their pros and cons and when each approach might appropriate. With that said, it’s not always the safest or most efficient method. The easiest way to convert a char to in int in C# is: int.Parse(m圜har.ToString()). ![]() It’s common to pull chars out of string, especially with regular expressions, and need to treat them like a true number. ![]()
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